Using corresponding angles, we find that \angle \text{AHB}  = \angle \text{FGH}, so \angle x = 37\degree

First identifying that \angle \text{FGH}  and    \angle \text{GHC} are alternate angles, we get

\angle \text{GHC}=41\degree

Then as \text{BE} is a straight line we can use the fact that angles on a straight line sum to 180\degree,

x=180\degree-41\degree=139\degree

Firstly, because angle HFG and angle EFC are vertically opposite, we get

\angle \text{EFC} = 48\degree

Secondly, because angle EFC and angle BCA (\angle x) are corresponding angles, we get

\angle \text{BCA} = x = 48\degree

Firstly, using the fact that angles FGJ and CDG are corresponding angles, we get

\angle \text{CDG } = 121\degree

Secondly, because angles on a straight line add to 180\degree, and angles CDG and CDA are on a straight line,

\angle \text{CDA } = 180 - 121 = 59\degree

Thirdly, again using the fact that angles on a straight line add to 180\degree, and angles CDA, BDE, and ADB (otherwise known as angle x) are on a straight line, we get

x + 50 + 59 = 180,\text{ so } x = 180 - 109 = 71\degree

Firstly, because angles BEF and EHJ are corresponding angles, we get

\text{angle EHJ } = 39\degree.

Next, because angles EDH and DHG are alternate angles, we get

\text{angle DHG } = 76\degree.

Then, because angles DHG, DHE, and EHJ are angles on a straight line and angles on a straight line add to 180\degree, we get

\text{angle DHE } = 180 - 76 - 39 = 65\degree

Finally, because angle DHE and angle x are vertically opposite angles, we get

x = 65\degree.

There are other possible methods for doing this question. As long as you’ve correctly applied angle fact, explained each step, and got the answer to be 71\degree, your answer is correct.