Distance-Time Graphs Worksheets, Questions and Revision

Distance-Time Graphs Worksheets, Questions and Revision

GCSE 4 - 5KS3AQAEdexcelOCRWJECFoundationOCR 2022WJEC 2022

Distance-Time Graphs

Distance-time graphs are a way of visually expressing a journey. With distance on the y-axis and time on the x-axis, a distance-time graph tells us how far someone/something has travelled and how long it took them/it to do so.

Make sure you are happy with the following topics before continuing:

distance time graph sections

Distance time graphs –  Key thinks to remember: 

1) The gradient of the line = speed

2) A flat section means no speed (stopped)

3) The steeper the graph the greater the speed

4) Negative gradient = returning to start point (coming back)

distance time graph sections
Level 4-5 GCSE KS3 AQA Edexcel OCR WJEC
Level 4-5 GCSE KS3 AQA Edexcel OCR WJEC

Using Distance Time Graphs

The graph below describes a journey that has several parts to it, each represented by a different straight line.

Part A: \bf{09:00 - 11:00}, the person travelled 30 km away from their starting point and that took them 2 hours.

Part B: \bf{11:00 - 12:00}, we can see that the line is flat, so the distance from their starting point did not change – they were stationary.

Part C: \bf{12:00 - 12:30}, they moved a further 30 km away from their starting point.

Part D: \bf{12:30 - 14:00}, they travelled the full 60 km back to where they began.

using distance time graphs

Calculate the speed – for each part of the journey:

\text{Speed} (S) = \dfrac{\text{Distance}(D)}{\text{Time}(T)}

Part A: \bf{09:00 - 11:00}

\text{Speed}= \dfrac{30}{2} = 15 km/h

Part B: \bf{11:00 - 12:00}

\text{Speed}= \dfrac{0}{1} = 0 km/h (Not moving)

Part C: \bf{12:00 - 12:30}

\text{Speed}= \dfrac{30}{0.5} = 60 km/h

Part D: \bf{12:30 - 14:00}

\text{Speed}= \dfrac{60}{1.5} = 40 km/h

From this we can see that the person travelled the fastest over part C.

Level 4-5 GCSE KS3 AQA Edexcel OCR WJEC

Example: Bike Ride

Valentina is going for a bike ride. Below is a distance-time graph that describes her full journey.

a) How long was she stationary for?

b) What was the total distance travelled during her journey?

c) What was her average speed in kilometres per hour between 17:15 and 17:45?

[3 marks]

distance time graphs bike ride example

a) We can see that the graph was flat for the duration of one big square. From the axis, we can see that two big squares total 15 minutes, therefore one big square is worth 7.5 minutes, so she was stationary for 7.5 minutes.

b) Valentina travelled away 25 km away from home, stopped briefly, and then travelled 25 km back home. Therefore, she travelled 50 km in total.

c) We need to calculate the gradient of the graph between 17:15 and 17:45. This period lasted for 30 minutes, which is equivalent to 0.5 hours – this is the “change in x”. During this period, she increased her distance from home from 5 km up to 25 km, meaning she travelled 20 km in total – this is the “change in y”. So, we get

\text{Gradient } = \dfrac{20}{0.5} = 40 km/h


Example Questions

So, making the words above seem more readable, we get:


  • 12:00 - 13:30, he travels from 0 miles away to 44 miles away;
  • 13:30 - 16:30, he stays in one place;
  • 16:30 - 18:30, he travels from 44 miles away to 0 miles away.


On a graph, this looks like:


distance time graphs example 1 answer


Looking at the graph, we can see that he runs at three different speeds during different portions of the race. The graph becomes less steep in the middle, so that won’t be his period of maximum speed, and the other two are hard to distinguish just by looking so we’ll work them both out.


Period 1:


\text{Gradient } = \dfrac{\text{distance travelled}}{\text{time taken}} = \dfrac{600 - 0}{72 - 0} = 8.33 m/s


Period 3:


\text{Gradient } = \dfrac{\text{distance travelled}}{\text{time taken}} = \dfrac{1,500 - 880}{282 - 180} = 6.08 m/s


Therefore, the fastest speed travelled by Chris during the race was 8.33 m/s, to 3 sf.

(a) Distance travel is,

\text{Total Distance } = 48 + 10 = 58 km


(b) She stopped for 30 mins at the 32 km mark.

The gradient of a distance time graph is the speed. Hence to find the fastest average speed we must find the steepest section of the graph.


This is the final section which cover 48 km in one hour, thus,


\text{Maximum speed } = 48 km/h


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