To find the missing value, substitute the given values into the equation.

When x = -1, we get y = \dfrac{1}{2} \times (-1) + 5 = 4.5

When x = 2, we get y = \dfrac{1}{2} \times (2) + 5 = 6

When y = 7, we get 7 = \dfrac{1}{2}x + 5

Subtract 5 from both sides of this equation to get

2 = \dfrac{1}{2}x

Multiplying both sides by 2, we immediately get x = 4. The completed table looks like:

Plotting these points and using them to draw the graph should look like:

Let’s rearrange this equation. Subtract 1 from both sides:

2y = 8x - 1

Then, divide both sides by 2:

y = 4x - \dfrac{1}{2}

So, the y-intercept is -\frac{1}{2}, and the gradient is 4 – so each time x increases by 1, y increases by 4.

This is enough information to draw the graph. The result should look like the figure below.

Rearranging this equation to be in the form y = mx +c, by adding 0.5 to both sides,

y = -0.5x + 0.5

So, the y-intercept is \dfrac{1}{2}, and the gradient is -\dfrac{1}{2} – so each time x increases by 1, y decreases by 0.5

The result should look like the figure below.

We can rearrange this equation by subtracting 2 from both sides:

2y = 3x - 2

Then, dividing both sides by 2:

y = \dfrac{3}{2}x - 1

So, the y-intercept is -1, and the gradient is \dfrac{3}{2} – so each time x increases by 1, y increases by 1.5

The result should look like the figure below.

We can rearrange this equation by subtracting 4x \text{ and } 2  from both sides:

y = -4x - 2

So, the y-intercept is -2, and the gradient is -4 – so each time x increases by 1, y decreases by 4

The result should look like the figure below.