Drawing Straight Line Graphs Worksheets | Questions and Revision

Drawing Straight Line Graphs Worksheets, Questions and Revision

Level 1-3
GCSE Maths Revision Guide

Drawing Straight Line Graphs

When asked to draw a straight line, there are 2 methods you can use, but it’s good to know both. 

  • Using a table/list of x, y coordinate values the line passes through, or
  • Using the equation of the line, in the form y = mx + c.

Make sure you are familiar with the following topics before continuing: 

Method 1: Table of Values Method

The table of values method involves calculating values of y for different values of x.

Example: Draw a graph for the line y = 2x - 3.

Step 1: Construct a table with suitable x values

Step 2: Find the values of y for each x value.

To work out the missing values, we use the equation like a formula, substituting the values from the table in, we get the following:

When x = -2, we get y = (2\times-2) - 3 = -7

When x = 0, we get y = (2\times0) - 3 = -3

When x = 2, we get y = (2\times2) - 3 = 1

When x = 4, we get y = (2\times4) - 3 = 5

Step 3: So, we know that the line passes through

(-2, -7), (0, -3), (2, 1) and (4, 5)

Now all that remains is to plot them on a pair of axes and draw a straight line through them. The result should look like the graph below.

Level 1-3

Method 2: Using y=mx+c

You can use y=mx+c to plot a straight line graph.

Example: Plot the straight-line graph with equation 3y + 9x = 12.

Step 1: Rearrange to get the equation in the form y=mx+c

\begin{aligned}(-9x)\,\,\,\,\,\,\,\,\,3y + 9x &= 12 \\(\div3)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3y &= -9x + 12 \\ y &= -3x+4\end{aligned}

Step 2: Plot the y-Intercept (i.e. the y-value at x=0

y-intercept = \bf{(0, 4)}

Step 3: Use the gradient to to plot the rest of the graph.

We know the gradient is - 3. Therefore, as the x value increases by 1, the y value decreases (due to negative gradient) by 3.

Using this information, we can plot the graph shown. 

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Example Questions

To find the missing value, substitute the given values into the equation.

 

When x = -1, we get y = \dfrac{1}{2} \times (-1) + 5 = 4.5

 

When x = 2, we get y = \dfrac{1}{2} \times (2) + 5 = 6

 

When y = 7, we get 7 = \dfrac{1}{2}x + 5

 

Subtract 5 from both sides of this equation to get

 

2 = \dfrac{1}{2}x

 

Multiplying both sides by 2, we immediately get x = 4. The completed table looks like:

 

Plotting these points and using them to draw the graph should look like:

Let’s rearrange this equation. Subtract 1 from both sides:

 

2y = 8x - 1

 

Then, divide both sides by 2:

 

y = 4x - \dfrac{1}{2}

 

So, the y-intercept is -\frac{1}{2}, and the gradient is 4 – so each time x increases by 1, y increases by 4.

 

This is enough information to draw the graph. The result should look like the figure below.

 

Rearranging this equation to be in the form y = mx +c, by adding 0.5 to both sides, 

 

y = -0.5x + 0.5

 

So, the y-intercept is \dfrac{1}{2}, and the gradient is -\dfrac{1}{2} – so each time x increases by 1, y decreases by 0.5

 

The result should look like the figure below.

 

We can rearrange this equation by subtracting 2 from both sides:

 

2y = 3x - 2

 

Then, dividing both sides by 2:

y = \dfrac{3}{2}x - 1

 

So, the y-intercept is -1, and the gradient is \dfrac{3}{2} – so each time x increases by 1, y increases by 1.5

 

The result should look like the figure below.

We can rearrange this equation by subtracting 4x \text{ and } 2  from both sides:

 

y = -4x - 2

 

So, the y-intercept is -2, and the gradient is -4 – so each time x increases by 1, y decreases by 4

 

The result should look like the figure below. 

GCSE Maths Revision Cards

Worksheets and Exam Questions

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(NEW) Drawing Straight Line Graphs Exam Style Questions - MME

Level 1-3 New Official MME

Drill Questions

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Straight Line (2)