# Similar Shapes and Enlargements Worksheets, Questions and Revision

GCSE 6 - 7GCSE 4 - 5KS3AQAEdexcelOCRWJECFoundationHigherEdexcel 2022OCR 2022WJEC 2022

## Similar Shapes

Two shapes are said to be mathematically similar if all of the angles in the shapes are equal, but the shapes are not necessarily the same size.

We relate two similar shapes of different sizes with a scale factor.

Make sure you are happy with the following topics before continuing.

Level 4-5 GCSE    ## Finding the Scale Factor

The first step for any similar shape question will often be to find the scale factor.

To do this we need to find two corresponding dimensions. For the example below we will use lengths.

(Surface area and volume can also be used, these are HIGHER ONLY)

Example: $A$ and $B$ are mathematically similar shapes.

Find the scale factor from $A$ to $B$. First we need to find two corresponding lengths.

We can see that the base of $A=2$ cm and $B=5$ cm.

To calculate the scale factor we divide the larger by the smaller:

$5 \div 2 = 2.5$

Scale factor = $2.5$

Note: Once the scale factor has been found it can be used to find missing lengths.

Level 4-5 GCSE    Level 6-7 GCSE    ## Similar Shapes: Area and Volume

(HIGHER ONLY) We can extend the idea of similarity further to include areas and volumes.

You can use the following table to find the corresponding measure of a mathematically similar shape. You multiply when finding the measure of a larger shape and divide for a smaller shape. See the examples below.

Level 6-7 GCSE    ## Example 1: Similar Shapes

Shapes $A$ and $B$ are mathematically similar. Find the missing side-length marked $x$. [2 marks]

Firstly, we must calculate the scale factor.

To do this we divide the base of shape B by the equivalent side length on shape A

$\textcolor{blue}{\text{Scale factor }}=15\div5=\textcolor{blue}{3}$

Now we have that the scale factor is $\textcolor{blue}{3}$, all we need to do to find $x$ is multiply $\textcolor{blue}{3}$ by the length of the corresponding side on the smaller shape. So we get

$x=\textcolor{blue}{3}\times3=9$

$x=9$cm

Level 4-5 GCSE    ## Example 2: Similar Shapes Area

$A$ and $B$ are mathematically similar shapes.

Work out the area of shape $A$. [3 marks]

Firstly, we will determine the scale factor that relates the side-lengths, dividing the larger by the smaller

$SF=28\div7=\textcolor{red}{4}$.

Now, if the scale factor for the side-lengths is $\textcolor{red}{4}$, then that means that the scale factor for the areas is:

$SF_A=\textcolor{red}{4}^2=\textcolor{blue}{16}$

Therefore, to find the area of the smaller shape, we need to divide the area of the bigger shape by the area scale factor: $16$. Doing so, we get

$\text{Area of A }=320\div\textcolor{blue}{16}=20 \text{ cm}^2$

Level 6-7 GCSE    ## Example 3: Similar Shapes Volume

$A$ and $B$ are mathematically similar shapes.

The volume of shape $A = 600\text{ cm}^3$

Work out the volume of shape $B$. [3 marks]

Firstly, we will determine the scale factor that relates the side-lengths, dividing the larger by the smaller

$SF=22\div11=\textcolor{red}{2}$.

Now, if the scale factor for the side-lengths is $\textcolor{red}{4}$, then that means the scale factor for the volumes is:

$SF_V=\textcolor{red}{2}^3=\textcolor{blue}{8}$

We know the volume of shape $A$ and the Volume scale factor $= \textcolor{blue}{8}$.

So we need to multiply the volume of $A$ by $SF_V$,

Volume of $B = 600 \times \textcolor{blue}{8} = 4800\text{ cm}^3$

Level 6-7 GCSE    ## Example Questions

a) To work out the scale factor, $SF$, we need to divide the given side-length on the bigger shape by the corresponding side of the smaller shape. Doing so, we get

$SF=5\div2=2.5$

Then, to find $x$, we must multiply this value by the corresponding side-length of the smaller shape. So, we get

$x=2.5\times3=7.5\text{ cm}$

b) To find the scale factor for the areas, $SF_A$, we must square the known scale factor:

$SF_A=2.5^2=6.25$

Now, to get the area of the bigger shape, we must multiply the area of the smaller one by this scale factor. Doing so, we get

$\text{Area of Q}=6\times6.25=37.5\text{ cm}^2$

a) To work out the scale factor, $SF$, we need to divide the given side-length on the bigger shape by the corresponding side of the smaller shape. Doing so, we get

$SF=42\div14=3$

b) Now we have the scale factor, we can apply it to the corresponding length to AC which is DF. Hence, we find that,

$\text{AC} =51\div3=17 \text{cm}$

a) To work out the scale factor, $SF$, we need to divide the given side-length on the bigger shape by the corresponding side of the smaller shape. Doing so, we get,

$SF=6\div3=2$

b) Now we have the scale factor, we can apply it to the corresponding length to BE which is BC. Hence, we find that,

$\text{AC} =4.4\times2=8.8 \text{cm}$

If the scale factor is 3 then the surface area is,

$3^2=9$

9 times bigger as shown by the calculation above. So we get

$\text{SA of larger sphere : SA of smaller sphere} = 9 : 1$

To work out the scale factor, $SF$, we need to divide the given side-length on the bigger shape by the corresponding side of the smaller shape. However, in this case we are not given two corresponding sides. Instead we can set an unknown length BE, as $x$ and form the equation,

$\dfrac{x}{5}=\dfrac{25}{x}$

Rearranging to find,

$x^2=125$

$x= \sqrt{125}$

Now we have two corresponding sides that we can use to find the scale factor,

$SF=\dfrac{25}{\sqrt{125}}$

## Related Topics

Level 1-3GCSEKS3

#### Basic Ratio Questions

Level 4-5Level 6-7GCSEKS3

## Worksheet and Example Questions

### (NEW) Similar Shapes (level 3-5) Exam Style Questions - MME

Level 4-5 GCSENewOfficial MME

### (NEW) Similar Shapes (level 6+) Exam Style Questions - MME

Level 6-7 GCSENewOfficial MME

Level 4-5 GCSE

Level 6-7 GCSE

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