y=mx+c Worksheets, Questions and Revision

y=mx+c Worksheets, Questions and Revision

GCSE 4 - 5KS3AQAEdexcelOCRWJECFoundationAQA 2022Edexcel 2022OCR 2022WJEC 2022

The Equation of a Straight Line (y=mx+c)

A straight line graph will always have an equation in the form y=mx+c. You need to be able to work out the equation of a straight line from a graph, as well as manipulate the equation itself.

There are 3 key skills you need to learn involving the equation of a straight line.

Make sure you are familiar with the following topics before continuing.

The straight line equation

Any straight line graph can be described  by the following equation:

\textcolor{red}{y}=\textcolor{limegreen}{m}\textcolor{red}{x}+\textcolor{blue}{c}

where \textcolor{red}x and \textcolor{red}y are the coordinates the line passes through, \textcolor{limegreen}m is the gradient and \textcolor{blue}c is the y-intercept (the y-coordinate where the line crosses the y axis).

Level 4-5 GCSE KS3 AQA Edexcel OCR WJEC
Level 4-5 GCSE KS3 AQA Edexcel OCR WJEC

Skill 1: Finding the Equation of a Straight Line

We need to be able to find the equation of a straight line from the graph.

Example: Find the equation of the straight line graph below

y=mx+c finding the equation of a straight line

Step 1: Find \textcolor{blue}{c}

We are looking for an equation of the form,

y=\textcolor{limegreen}{m}x+\textcolor{blue}{c}

We know \textcolor{blue}{c} = y-intercept. Looking at the graph, we can see it crosses the axis at - 1, therefore we have \textcolor{blue}{c=-1}.

y=mx+c finding the gradient of a straight line

Step 2: Find the gradient (\textcolor{limegreen}{m})

Then, to work out the gradient,

\text{Gradient } = \dfrac{\textcolor{red}{\text{change in }y}}{\textcolor{blue}{\text{change in }x}}

The triangle we have drawn has height 4 and width 2, so we get,

m=\text{gradient}=\dfrac{\textcolor{red}{4}}{\textcolor{blue}{2}}=\textcolor{limegreen}{2}

Therefore, the equation of the straight line is,

y=\textcolor{limegreen}{2}x\textcolor{blue}{-1}

Level 4-5GCSEKS3AQAEdexcelOCRWJEC
Level 4-5 GCSE KS3 AQA Edexcel OCR WJEC

Skill 2: Finding the Equation of a Line Through Two Points 

Finding the equation of a straight line between two points is an important skill.

Example: Find the equation of the line that passes through (-3, 1) and (2, -14).

Step 1: Finding the gradient,

m=\text{gradient}=\dfrac{(-14)-1}{2-(-3)}=\dfrac{-15}{5}=-3

Now we know that m=-3, we know that our equation must take the form,

y=-3x+c

Step 2: Substitute the x and y values of one co-ordinate, say x = -3, y=1, into the equation,

1=(-3)\times(-3)+c=9+c

Step 3: Rearrange to solve for c,

c=1-9=-8

Step 4: Now we have all the components of the equation of a line, we can write the resulting equation as,

y=-3x-8

Level 4-5 GCSE KS3 AQA Edexcel OCR WJEC
Level 4-5 GCSE KS3 AQA Edexcel OCR WJEC

Skill 3: Rearranging Equations into the form y=mx+c

It is often necessary to rearrange the equation of a line to get it in the form y=mx+c. This is essential for finding the gradient and y-intercept.

Example: Find the gradient and y-intercept of the line x+2y=14.

We want to rearrange this equation to make y the subject. So, subtracting x from both sides, we get

2y=-x+14

Then, dividing both sides by 2, we get

y=-\dfrac{1}{2}x+7

Therefore, the gradient is -\dfrac{1}{2} and the y-intercept is 7.

Level 4-5 GCSE KS3 AQA Edexcel OCR WJEC

Example Questions

We want an equation of the form

 

y=mx+c

 

So, we need to find the gradient, m, and y-intercept, c.

 

Firstly, looking at the graph we can see that the y-intercept is 2, so c=2.

 

Now, we will find the gradient by drawing a triangle underneath the line in question.

y=mx+c example 1 answer

The triangle we have drawn has height 1 and width 3, so we get

 

m=\text{gradient}=\dfrac{1}{3}

 

Therefore, the equation of the line is

 

y=\dfrac{1}{3}x+2

We want an equation of the form

 

y=mx+c

 

So, we need to find the gradient, m, and y-intercept, c.

 

Firstly, we will find the gradient by dividing the difference in the y coordinates by the difference in the x coordinates:

 

m=\text{gradient}=\dfrac{-6-34}{-3-2}=\dfrac{-40}{-5}=8

 

Therefore, the equation of the line is

 

y=8x+c

 

Then, to find c we will substitute one pair of coordinates that the line passes through into the equation and rearrange. Here, we’ll pick (2, 34). Subbing this in, we get

 

34=8\times2+c=16+c

 

Subtracting 16 from both sides, we get

 

c=34-16=18

 

Therefore, the equation of the line is

 

y=8x+18.

We want an equation of the form

 

y=mx+c

 

So, we need to find the gradient, m, and y-intercept, c.

 

Firstly, looking at the graph we can see that the y-intercept is - 1, so c=-1.

 

Now, we will find the gradient by drawing a triangle underneath the line in question. Hence

m=\text{gradient}=\dfrac{3}{2}y=mx+c example 3 answer

 

Therefore, the equation of the line is

 

y=\dfrac{3}{2}x-1

Related Topics

MME

Gradients of Straight Line Graphs

Level 4-5GCSEKS3
MME

Rearranging Formulae

Level 4-5Level 6-7GCSEKS3

Worksheet and Example Questions

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