## What you need to know

**Things to remember:**

- We look at terms individually.
- We include the operator (+ or -) before the numbers and variables as part of the term.
- If there isn’t an operator before a term, then it is a +.

There are five different types of terms:

**Numbers by themselves**

4 -8 1 -1 0.5 0.25 \frac{3}{5} \frac{12}{13}

* ***Variables by themselves**

a g h z

** ****Variables multiply by numbers**

2a 5g 0.4h \frac{3}{5}z

** ****Variables multiplied together**

ab gh ch bz

** ****Variables and numbers multiplied together**

2ab fgh 0.4ch \frac{3}{5}bz

*How many terms are there in the following expression?*

3x+3-4+y-24+3xy

* *If we read it going from left to right we can see: 3, x, 3, 4, y, 24, 3, x, and y. So there are 9 terms… But not quite, because the last 3, x, and y are actually together to make 1 term. So, the best way is to split it up the terms by the operators (+ and -)

(3x)(+3)(-4)(+y)(-24)(+3xy)

Now that we have split them up, we can just count up the brackets; there are 6 terms.

*How many terms are there in the following expression?*

9z^2-5x-13y+6y

(9z^2)(-5x)(-13y)(+6y)

There are 4 terms in the expression

*How many terms are there in the following expression?*

a^3b^2-5xyz+2-2

*Hint: **Although the 2-2=0, we have to count the terms separately first.*

(a^3b^2)(-5xyz)(+2)(-2)

There are 4 terms in the expression

## KS3 Maths Revision Cards

(77 Reviews) £8.99## Example Questions

**Question 1:** How many terms are there in the following expression?

y-7z^2+3y+2x-4+3x+2

y-7z^2+3y+2x-4+3x+2

(y)(-7z^2)(+3y)(+2x)(-4)(+3x)(+2)

There are 7 terms in the expression

**Question 2:** How many terms are there in the following expression?

-a+a^2-a^3+ab-ab^2+ab^3

-a+a^2-a^3+ab-ab^2+ab^3

(-a)(+a^2)(-a^3)(+ab)(-ab^2)(+ab^3)

There are 6 terms in the expression

## KS3 Maths Revision Cards

(77 Reviews) £8.99- All of the major KS2 Maths SATs topics covered
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