## What you need to know

**Things to remember:**

- We add as many zeros as there were at the ends of the two numbers.
- The final answer could have more zeros than there were at the start..

Let’s start by recapping what happens when we multiply numbers, by 10, 100, and 1000.

Number Multiplying by 10 Multiplying by 100 Multiplying by 1000

15 150 1500 15000

183 1830 18300 183000

250 2500 25000 250000

So, when we multiply a number by a power of 10, we add as many 0s as there in the power of 10. It is also important to notice how we can write numbers than end in lots of 0s.

183000=183\times1000

150=15\times10

*What is the value of 37\times52000*

* *

We can do this in four steps.

**Step 1:** Write the number with the zeros as a multiplication.

52000=52\times1000

**Step 2:** Replace the number with the 0s with the multiplication found in **Step 1**.

37\times52000=37\times52\times1000

**Step 3: **Multiply the numbers without the 0s.

37\times52=1924

**Step 4: **Multiply by the power of 10 (add the zeros)

** **

37\times52000=1924000

** **

Sometimes though, both numbers will have zeros.

*What is the value of 9700\times35000*

* *

We can do this in five steps.

**Step 1:** Write the numbers with the zeros as a multiplication.

9700=97\times100

35000=35\times1000

**Step 2:** Replace the numbers with the 0s with the multiplications found in **Step 1**.

9700\times35000=97\times100\times35\times1000

**Step 3: **Rearrange so the numbers without 0s are together

9700\times35000=97\times35\times1000 \times100

**Step 4: **Multiply the numbers without the 0s.

97\times35=3395

**Step 4: **Multiply by the powers of 10 (add the zeros)

** **

9700\times35000=3395\times1000 \times100 =3395000000

## KS3 Maths Revision Cards

(77 Reviews) £8.99## Example Questions

**Question 1:** Find the value of 13\times5800

**Step 1:** Write the number with the zeros as a multiplication.

5800=58\times100

**Step 2:** Replace the number with the 0s with the multiplication found in **Step 1**.

13\times5800=13\times58\times100

**Step 3: **Multiply the numbers without the 0s.

13\times58=754

**Step 4: **Multiply by the power of 10 (add the zeros)

** **

13\times5800=75400

**Question 2:** Find the value of 270\times6100

**Step 1:** Write the numbers with the zeros as a multiplication.

270=27\times10

6100=61\times100

**Step 2:** Replace the numbers with the 0s with the multiplications found in **Step 1**.

270\times6100=27\times10\times61\times100

**Step 3: **Rearrange so the numbers without 0s are together

270\times6100=27\times61\times10 \times100

**Step 4: **Multiply the numbers without the 0s.

27\times61=1647

**Step 4: **Multiply by the powers of 10 (add the zeros)

** **

270\times6100=1647\times10 \times100 =1647000

## KS3 Maths Revision Cards

(77 Reviews) £8.99- All of the major KS2 Maths SATs topics covered
- Practice questions and answers on every topic

- Detailed model solutions for every question
- Suitable for students of all abilities.