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Parallel and Perpendicular Lines

GCSELevel 6-7Edexcel iGCSE

Parallel and Perpendicular Lines Revision

Parallel and Perpendicular Lines

Parallel Lines – are always the same distance apart and never meet (they have the same gradient).

Perpendicular Lines – meet at a right angle (the gradients of perpendicular lines multiply to -1).

Before continuing this topic, recap the following:

Parallel Lines – Same Gradient

Parallel lines have the same gradient.

Equation of a straight line: y=\textcolor{#10a6f3}{m}x+c

\textcolor{#10a6f3}{m} \rightarrow gradient

c \rightarrow y- intercept

For lines to be parallel, the value of \textcolor{#10a6f3}{m} must be the same. 

Let’s take a look at the following lines:

y=\textcolor{#10a6f3}{2}x+1 (*)

y\textcolor{#10a6f3}{-2}x=5 (**)

y=\textcolor{#10a6f3}{2}x -4 (***)

The second equation (**) must be rearranged into the form

y=\textcolor{#10a6f3}{m}x+c , before comparing the gradients: 

y=\textcolor{#10a6f3}{2}x+5

These lines all have a gradient of \textcolor{#10a6f3}{2} \, (m=2) . These straight line equations are shown on the graph to the right.

Level 6-7GCSEEdexcel iGCSE

Perpendicular Lines – Right Angles

Perpendicular lines meet at a right angle. When we multiply the gradients of a pair of perpendicular lines they multiply to \textcolor{#00d865}{-1}.

Another way of looking at this concept is to think of the perpendicular gradient as the ‘opposite sign and reciprocal’.

For instance, let’s say we have a straight line with a gradient: \textcolor{#00d865}{m=2}

Then the perpendicular gradient would be: \textcolor{#00d865}{m=-\dfrac{1}{2}}

\textcolor{#00d865}{2}\times\textcolor{#00d865}{-\dfrac{1}{2}}=\textcolor{#00d865}{-1}

Let’s take a look at the following lines:

y=\textcolor{#00d865}{3}x+1

y=\textcolor{#00d865}{-\dfrac{1}{3}}x+2

These lines are perpendicular as: \textcolor{#00d865}{3}\times\textcolor{#00d865}{-\dfrac{1}{3}}=\textcolor{#00d865}{-1}. These straight line equations are shown on the graph to the right.

Level 6-7GCSEEdexcel iGCSE

Example 1: Parallel Lines

Find the equation of a straight line that is parallel to \textcolor{#f95d27}{y=3x+5} and passes through (1,-2) 

Equation of the parallel line: y=3x+c

[3 marks]

c is the y \,intercept and can take any value. However, because we know the line passes through the coordinate (1,-2), we can find the exact value of c

To do this, we substitute x=1 and y=-2 

-2=3(1)+c \rightarrow c=-5 \rightarrow \textcolor{#f21cc2}{y=3x-5}
Level 6-7GCSEEdexcel iGCSE

Example 2: Perpendicular Lines

Find the equation of a straight line that is perpendicular to

\textcolor{#f95d27}{y=\dfrac{2}{3}x+1} and passes through (2,1) 

[3 marks]

Equation of the perpendicular line: y=-\dfrac{3}{2}x+c 

c is the y \,intercept and can take any value. However, because we know the line passes through the coordinate (2,1), we can find the exact value of c

To do this, we substitute x=2 and y=1 

1=-\dfrac{3}{2}(2)+c \rightarrow c=4 \rightarrow \textcolor{#f21cc2}{y=-\dfrac{3}{2}x+4}
Level 6-7GCSEEdexcel iGCSE

Parallel and Perpendicular Lines Example Questions

After some rearrangement, to get the equations in the form of y=mx+c, we get the following:

a) y=2x+5 

b) y=-3x+6

c) y=2x-3 

d) y=\dfrac{1}{3}x+9 

a) and c) are parallel, as the gradients are the same.

b) and d) are perpendicular, as when you multiply the gradients together you get -1.

We first need to rearrange the equation into the form of  y=mx+c:

y=8x+11

Equation of parallel line: 

y=8x+c

Substituting x=2 and y=5

5=8(2)+c \rightarrow c=-11 \rightarrow y=8x-11

We first need to rearrange the equation into the form of y=mx+c:

y=-\dfrac{1}{5}x+10

Equation of perpendicular line: 

y=5x+c

Substituting x=2 and y=12

12=5(2)+c \rightarrow c=2 \rightarrow y=5x+2

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